Given a 2D array, print it in spiral form. See the following examples.
Input:
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
Output:
1 2 3 4 8 12 16 15 14 13 9 5 6 7 11 10
Input:
1 2 3 4 5 6
7 8 9 10 11 12
13 14 15 16 17 18
Output:
1 2 3 4 5 6 12 18 17 16 15 14 13 7 8 9 10 11
Solution:
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#include <stdio.h>
#define R 3
#define C 6
void spiralPrint(int m, int n, int a[R][C])
{
int i, k = 0, l = 0;
/* k – starting row index
m – ending row index
l – starting column index
n – ending column index
i – iterator
*/
while (k < m && l < n)
{
/* Print the first row from the remaining rows */
for (i = l; i < n; ++i)
{
printf(“%d “, a[k][i]);
}
k++;
/* Print the last column from the remaining columns */
for (i = k; i < m; ++i)
{
printf(“%d “, a[i][n-1]);
}
n–;
/* Print the last row from the remaining rows */
if ( k < m)
{
for (i = n-1; i >= l; –i)
{
printf(“%d “, a[m-1][i]);
}
m–;
}
/* Print the first column from the remaining columns */
if (l < n)
{
for (i = m-1; i >= k; –i)
{
printf(“%d “, a[i][l]);
}
l++;
}
}
}
/* Driver program to test above functions */
int main()
{
int a[R][C] = { {1, 2, 3, 4, 5, 6},
{7, 8, 9, 10, 11, 12},
{13, 14, 15, 16, 17, 18}
};
spiralPrint(R, C, a);
return 0;
}
/* OUTPUT:
1 2 3 4 5 6 12 18 17 16 15 14 13 7 8 9 10 11
*/
Please Leave comment if you have doubts. Give ur solution thru comments.
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